Calculate Energy Required to Turn Ice Into Steam

Ascertain Energy Required to Turn Ice Into Steam This worked model issue exhibits how to ascertain the vitality required to raise the temperature of an example that remembers changes for stage. This issue finds the vitality required to transform cold ice into hot steam. Ice to Steam Energy Problem What is the warmth in Joules required to change over 25 grams of - 10  °C ice into 150  °C steam?Useful information:heat of combination of water 334 J/gheat of vaporization of water 2257 J/gspecific warmth of ice 2.09 J/g ·Ã‚ °Cspecific warmth of water 4.18 J/g ·Ã‚ °Cspecific warmth of steam 2.09 J/g ·Ã‚ °CSolution:The all out vitality required is the total of the vitality to warm the - 10  °C ice to 0  °C ice, softening the 0  °C ice into 0  °C water, warming the water to 100  °C, changing over 100  °C water to 100  °C steam and warming the steam to 150  °C. To get the last worth, first ascertain the individual vitality esteems and afterward include them up.Step 1: Heat required to raise the temperature of ice from - 10  °C to 0  °C Use the formulaq mcÃŽTwhereq heat energym massc explicit heatÃŽT change in temperatureq (25 g)x(2.09 J/g ·Ã‚ °C)[(0  °C - 10  °C)]q (25 g)x(2.09 J/g ·Ã‚ °C)x(10  °C)q 522.5 JHeat required to raise the temperature o f ice from - 10  °C to 0  °C 522.5 JStep 2: Heat required to change over 0  °C ice to 0  °C waterUse the recipe for heat:q m ·ÃŽHfwhereq heat energym massÃŽHf warmth of fusionq (25 g)x(334 J/g)q 8350 JHeat required to change over 0  °C ice to 0  °C water 8350 JStep 3: Heat required to raise the temperature of 0  °C water to 100  °C waterq mcÃŽTq (25 g)x(4.18 J/g ·Ã‚ °C)[(100  °C - 0  °C)]q (25 g)x(4.18 J/g ·Ã‚ °C)x(100  °C)q 10450 JHeat required to raise the temperature of 0  °C water to 100  °C water 10450 JStep 4: Heat required to change over 100  °C water to 100  °C steamq m ·ÃŽHvwhereq heat energym massÃŽHv warmth of vaporizationq (25 g)x(2257 J/g)q 56425 JHeat required to change over 100  °C water to 100  °C steam 56425Step 5: Heat required to change over 100  °C steam to 150  °C steamq mcÃŽTq (25 g)x(2.09 J/g ·Ã‚ °C)[(150  °C - 100  °C)]q (25 g)x(2.09 J/g ·Ã‚ °C)x(50  °C)q 2612.5 JHeat required to change over 100  °C st eam to 150  °C steam 2612.5Step 6: Find all out warmth energyHeatTotal HeatStep 1 HeatStep 2 HeatStep 3 HeatStep 4 HeatStep 5HeatTotal 522.5 J 8350 J 10450 J 56425 J 2612.5 JHeatTotal 78360 JAnswer:The heat required to change over 25 grams of - 10  °C ice into 150  °C steam is 78360 J or 78.36 kJ.